2 ants start simultaneously from two ant holes towards each other. 1st ant covers 8% of the distance between two ant holes in 3 hrs. 2nd ant covers 7/120 of the dist. in 2.5 hrs. find the speed ( feet/hr ) of 2nd ant if 1st ant travelled 800 feet to the meeting point.

1) 25
2) 36
3) 42
4) 35
5) 45

• Meeting point
  
  Ant 1 ..................................................|......................................Ant 2
  
  
  
  Let Total distance = d feets
  
  S1 = (8d) / 300 ft/hr --------- equation(1)
  S2 = (7d) / ( 120 * 2.5 ) ft / hr ---------equation(2)
  
  Time taken ( T1 ) by Ant 1 to cover 800 ft = (30000) / d
  in the same time Ant 2 will cover = S2 * T1 = 700 ft
  
  Total distance to be covered by Ant 2 = 800+700
  
  So put d = 1500 in equation 2
  
  S2 = 35 ft/hr (Answer)
• 8 years agoHelpfull: Yes(1) No(0)