if (9+9^2+9^3+.......9^n)is divide 6 ,reminder will be ? (n is a multiples of 11)

• 3n will be the remainder when given term is divided by 6
  now since n is a multiple of 11 then
  3(11)=33 i.e. rem =3
  again 3(22)==66 rem =0
  3(33)=99 rem=3
  if n is odd then remainder is 3
  if n is even the remainder is 0
  ans remainder is 3,0
• 11 years agoHelpfull: Yes(36) No(0)
• if n is odd then remainder is 3 and when n is even then remainder is 0....
• 11 years agoHelpfull: Yes(12) No(0)
• 3 is the ans
  
• 11 years agoHelpfull: Yes(8) No(6)
• remainder is 3 when 6 divides any power of 9.
  So, we get 3n as remainder.
  As n is a multiple of 11, assuming n as 11 itself and dividing by 6, rem is 3
  so, 3 is the Ans.
  
• 11 years agoHelpfull: Yes(4) No(2)
• 1 or 3 or 5 ........
• 11 years agoHelpfull: Yes(2) No(14)
• it can be written as 9(9^11-1)/8
  when power of 9 divided by 6 always remainder will be 3.
  hence answer=3
• 11 years agoHelpfull: Yes(2) No(1)
• let n=1;
  9%6=3;
  3+9+27+81..........[up to 11 term]
  lets take the remaider up to 11th term..
  3+3+3+.....[11 times]
  33%6=3
  ans=3
• 9 years agoHelpfull: Yes(1) No(1)
• ans will be 3 bcz here given the value of n=1
• 8 years agoHelpfull: Yes(0) No(0)
• The sum of this is 9(9^11-1)/8
  and 6 can be written as 2*3 so 9 id devisable by 3 and (9^11-1) is always even so it devisable by 2 so reminder is 0
• 7 years agoHelpfull: Yes(0) No(0)