. there r some steps. i come down 7 steps then see a man at bottom. then he comes up and i go down at same speed(my speed). when 4 steps r remaining for me i find tht man has reached the top. for my single step downwards he took 2 steps up. find total steps.

22 steps : suppose there are R steps and and speed of the person who is asking d question be s...so total distance travelled by questioner when the other man is also moving= (R-7)-4 steps....in the same time dat man moves a distance of R steps...and both takes same time...therefore (R-11)/s = R/2s (as his speed is double) => R=22 steps
11 years agoHelpfull: Yes(10) No(3)
22 steps

If I took x steps during man's journey upwards, then
7+x+4=2x where 2x is number of total steps
x=11
total steps =2x=22 steps
11 years agoHelpfull: Yes(6) No(4)
18
7+x+4=total steps
other man step=2*my step
when 4 step left other man is on top=7*2=14
14+4=18
11 years agoHelpfull: Yes(2) No(10)
no.of steps=p
the remaining steps for the first person
=p-(7+4)=p-11
now given for my single step downwards he took 2 steps up
2(p-11)=p
p=22
11 years agoHelpfull: Yes(2) No(0)
suppose I have go down x steps, after noticing him. so total no. of steps is x+7+4, and while I came down, he covered all steps and covered 2x steps.
2x=x+7+4
x=11
total steps 22
11 years agoHelpfull: Yes(1) No(0)

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