one day a slug fell into a hole that was 19 feet deep.each day he climbed up 4 feet.at night he slid back 2 feet.how many days did it take him to climb out of the hole?

• one day a slug fell into a hole that was 19 feet deep.each day he climbed up 4 feet.at night he slid back 2 feet.
  So in 1 day , he went up by 2 ft.
  in 8 days, he went up by 16 ft.
  In 9 th day (after 3/4 th day ), he went up by 19 ft.
  so 8 and 3/4 days .
• 13 years agoHelpfull: Yes(6) No(2)
• 9 days
  8*2 =16
  remaining = 3
  next day he will climb it
  hence 9 day
• 13 years agoHelpfull: Yes(2) No(0)
• 4 1/2 days
• 13 years agoHelpfull: Yes(0) No(1)
• only nine days required as,8*2=16 ft in 8 dats in the ninth day it will be at the surface
  
• 13 years agoHelpfull: Yes(0) No(0)
• per day he climb feet=4
  one day he slid back 2 feet
  so ttl day to climb out= 4*4-2+4+1= 5days
• 13 years agoHelpfull: Yes(0) No(0)