Simple question on average age. Smith likes a,b,c weigheted separately 1st a,b,c then a& b, b&c , c&a and at last a,b,c, the last weight was 167,then what will be the avg weight of the 7 weight?

• a+b+c =167 ;
  total wt of 7 weighings = a + b + c+ (a+ b) + (b+c) + (c+a) + (a+b+c)
  = 4(a+b+c)
  so avg of 7 weighs = 167*4/7 = 95.43 approx
• 13 years agoHelpfull: Yes(49) No(2)
• avg of 7 weighings = [a + b + c+ (a+ b) + (b+c) + (c+a) + (a+b+c)]/7
  = 4(a+b+c)/7
  = 167*4/7 = 95.43
• 13 years agoHelpfull: Yes(12) No(0)
• the following are being weighed:
  a,b,c,a+b,b+c,c+a,a+b+c
  last weight = a+b+c=167
  the average weight of 7 will be= [a+b+c+(a+b)+(b+c)+(c+a)+(a+b+c)]/7
  =4(a+b+c)/7
  =4(167)/7
  =95.428
  which is approximately equal to 95.43
• 13 years agoHelpfull: Yes(7) No(0)
• a+b+c=167
  ttl wt of 7 weighing=A+b+c+(a+b)+(b+c)+(c+a)+(a+b+c)=4a+4b+4c
  = 4(a+b+c)=4*167= 668
  so average of 7 weighning= 668/7= 95.428
  
• 13 years agoHelpfull: Yes(5) No(1)