there is a circle with 2 traingle inscribed in it making a star.the traingle is equilateral of side 12.u have to tell the area of remaining portion of circle

• area of remaining portion = area of circle - area of one of the equilateral triangle -area of 3 small equilateral triangle formed by star....and radius of circumscribing circle=4*1.73 ar= pi*(4*1.73)*(4*1.73)-sqrt((18)*(18-12)*(18-12)*(18-12))-3*sqrt((6)(6-4)(6-4)(6-4))=150.72-62.28-20.76=67.68 sq units
• 11 years agoHelpfull: Yes(7) No(9)
• Now since both the triangles are equilateral the intersecting lines divide each other proportionally forming 6 small triangles of side 4u. and a quadrilateral.
  Required area is= (Area of the circle)-(3*area of small triangles + area of big triangle). Area of the circle is found by using the centroid theorem. Radius of the circumscribing circle is equal to (2/3)*height of equilateral triangle. The entire thing turn out to 77.61
• 11 years agoHelpfull: Yes(3) No(2)
• 67.658 sq. units
• 11 years agoHelpfull: Yes(0) No(4)
• 26
  remaining area=3.14*r*r-2*root3*12*12
• 11 years agoHelpfull: Yes(0) No(2)