A speaks truth 70% of the time; B speaks truth 80% of the time. What is the probability that both are contradicting each other?

• when A speaks d truth,B contradicts him
  when B speaks d truth,A contradicts him
  i.e d probablity tht both are contradicting each other is
  =[((7/10)*(1-(8/10)))+((8/10)*(1-(7/10)))]
  =[((7/10)*(2/10))+((8/10)*(3/10))]
  =[(14/100)+(24/100)]
  =[38/100]
  19/50
• 13 years agoHelpfull: Yes(15) No(2)
• Contradictory situation
  
  A Truth B Wrong
  A wrong B truth
  
  so,
  
  (7/10*2/10)+(3/10+8/10)
  =14/100+24/100
  38/100
  
  So, 38% times they contradict each other...
• 13 years agoHelpfull: Yes(9) No(1)
• Contradicting situations arise when either a is telling the truth and b doesn't or when b is telling the truth and a doesn't.
  
  So probabillity will be
  ((7/10)*(2/10))+((3/10)*(8/10))
  14/100+24/100
  38/100
  
  i.e. 38%
• 13 years agoHelpfull: Yes(5) No(1)
• for A
  prob for truth=70/100
  prob for lie=1-70/100=30/100
  for B
  prob of truth=80/100
  prob of lie=20/100
  prob of contradicting=70/100*20/100+80/100*30/100=19/50
  
• 13 years agoHelpfull: Yes(3) No(1)