In a family 7 children dont eat spinach, 6 dont eat carrot, 5 dont eat beans, 4 dont eat spinach & carrots, 3 dont eat carrot & beans, 2 dont eat beans & spinach. One doesnt eat all 3. Find the no. of children.

• since,n(aUbUc)=n(a)+n(b)+n(c)-n(a intersection b)-n(a intersection c)-n(b intersection c)+n(a intersection b intersection c)
  therfore,n(aubuc)=7+6+5-4-3-2+1=10
• 13 years agoHelpfull: Yes(15) No(2)
• n(aUbUc)=n(a)+n(b)+n(c)-n(a intersection b)-n(b intersection c)-n(a intersection c)+n(a intersection b intersection c)
  
  ->n(aUbUc)=7+6+5-4-3-2+1=10
• 13 years agoHelpfull: Yes(4) No(0)
• total=10
  total=(AuBuC)=A+B+C+(AuBnc)+(AuCnB)+(BuCna)+(AnBnC)
  total=2+3+1+1+2+1=10
• 13 years agoHelpfull: Yes(0) No(0)