for rs600 karan can buy a maximum of 24cups of tea and for rs1000 he can buy a max of 15 cups of cofee.he has rs2200 in his pocket & purchases 8 cups of tea.what is the max no of cups of cofee karan can purchase with remaining money?
a.33 b.32 c.31 d.27

• rate of tea cup can be directly seen as 25per cup.
  to calculate rate of coffee cup, we have to understand the line carefully,
  it is saying "maximum of 15 cups", ie the rate has been minimized so as to buy it maximum.
  if we calculate the rate of cup then it will come around 66.66. but this is the maximum rate of the 15 cups to be completely purchased.
  here we should consider minimum value of x for which 16*(x)>1000
  and the minimum value is 63.
  if we buy 16 cups at the rate of 63, we cannot buy the 16th cup at this rate.
  hence 63/coffee is the minimized(bargained rate) to purchase maximum coffee cup.
  
  now we can clearly see that no of coffee cups that can be purchased is (2000/63)=31.74
  hence 31 cups can be purchased.
  Thanks
• 11 years agoHelpfull: Yes(16) No(2)
• 30 cups of coffee.
  
  explanation:
  price of a cup of tea =600/24=25
  price of 8 cups of tea=25*8=200
  
  remaining amount=2200-200=2000
  in rs 1000 he can buy max of 15 cups of coffee.
  so he can purchase 30 cups of coffee.
• 11 years agoHelpfull: Yes(6) No(2)
• the answer will be 30. but it is not among the options
• 11 years agoHelpfull: Yes(5) No(4)
• 600=24T max
  hence cheapest T=25
  1000=15C max
  hence cheapest C=200/3
  Therefore, 8C=200 cheapest.. can be more than that
  Therefore max money left is 2000
  2000=30 cheapest cups of coffee( max)
  The answer has to be less than 30
  on 27 satisfies
  27 d is the ans
• 11 years agoHelpfull: Yes(1) No(2)
• 31..
  1 cup of tea costs = 600/24 = 25/-
  1 cup of coffee costs = 1000/15 = 66.666/-
  8 cups of tea cost = 25*8 = 200/-
  he has 2200/- with him..
  cost of x cups of coffee = total - cost of 8 cups of tea = 2200 - 200 = 2000/-
  thus, x cups of coffee for 2000/- = 2000/66 = 30.303030 = 31
• 11 years agoHelpfull: Yes(1) No(3)
• tremain value
• 11 years agoHelpfull: Yes(0) No(1)