a train met with an accident 60 km away from Amsterdam station.It completed the remaining journey at 5/6 th of the previous speed and reached Trent Bridge station 1 hour 12 in late.Had accident taken place 60 km further ,it woud have been only 1 hour late a What is th normal speed of train what ist he distance between Amsterdam and Trent Bridge ?
explanation is needed

• LET THE NORMAL SPEED OF TRAIN BE "x km/hr"
  LET THE TOTAL DISTANCE BE "y km"
  
  -Accident occur after 60km from Amsterdam i.e; train has travelled 60km with normal speed. hence time taken at normal speed till accident= (60/x) hr.
  -Rest distance from accident to Trent Bridge= (y-60) km.
  -Speed for rest of distance= (5/6)x = (5x/6).
  -time taken to travel rest distance= (y-60)/(5x/6) = ((6(y-60))/5x)
  -if accident would not have occurred den time taken = y/x
  -train late by 1hr 12min= 1+(12/60)= 6/5 hr
  - Hence 1st equation is =
  (60/x)+ ((6(y-60))/5x) = y/x + 6/5 ------eqn 1
  - similarly eqn 2 can be written as
  (120/x) + ((6(y-120))/5x) = y/x + 1 ------eqn 2
  
  simplify and solve both the equations...
  ans will be x = 60 km/hr and y = 420 km
  Thanks.
• 11 years agoHelpfull: Yes(39) No(4)
• normal speed of the train 60km/hr.
  &
  distance between Amsterdam and Trent Bridge is 420 km
  
  
  explanation
  let normal speed of the train be x km/hr and distance between Amsterdam and Trent Bridge be y km.
  normally train takes y/x hrs to reach Trent Bridge.
  in case 1
  time taken till accident=60/x hr
  time taken 2 cover remaining distance= 6 * (y-60)/5x
  according 2 question,
  60/x + 6 * (y-60)/5x= y/x + 1.2 (converting minute into hour)
  on solving this equation we get,
  y-6x=60 .................(1)
  
  now in case 2
  time taken till accident=(60+60)/x hr=120/x hr
  time taken 2 cover remaining distance= 6 * (y-120)/5x
  according 2 question,
  120/x + 6 * (y-120)/5x= y/x + 1
  on solving this equation we get,
  y-5x=120 .................(2)
  
  on solving (1) and (2) we get
  x=60
  y=420
• 11 years agoHelpfull: Yes(13) No(0)
• speed of train is :60kmhr
  and distance bw amsterdam and trent bridge is :50km
• 11 years agoHelpfull: Yes(6) No(6)
• 5/6 of the speed means 6/5 of the time
  6/5T=5/5T+1/5T
  here it is given that car is late by 1 hour 12 minutes means6/5 hours
  -1/5T=6/5hours
  T=6 hours
  this implies car took 6 hours at normal speed from accident point to trent bridge
  2nd condition
  If accidnent took place 60Km further car goes late by 1 hour
  1/5T=1 hour
  T= 5 hours
  Distance travelled in 1 hour at normal speed =120-60=60
  Speed = 60Km/hour
  Total distance = 60*6 +60(distance from amsterdam to accident point) =420 Km/h
• 11 years agoHelpfull: Yes(5) No(1)
• Normal speed of train =60km/hr.
  Distance between Amsterdam & Trent Bridge=420km
  Exp:
  Let normal speed be a;
  Actual distance be b;
  Actual time = a/b;
  Time taken for 60km=60/a;
  time taken for remaining distance= (b-60)/(5a/6)= 6*(b-60)/5a = (6b-360)/5a;
  total time = (6b-360)/5a+60/a= 6b-60/5a;
  time difference = 6b-60/5a-b/a= 1hr 12 min= 6/5;
  => b=6a+60.........(i);
  similarly
  6b-120/5a-b/a=1;
  => b=5a+120........(ii);
  solving i and ii
  a=60 and b=420
  
• 11 years agoHelpfull: Yes(3) No(5)
• No need to find speed in this one.
  Let the total Distance bet Amster and TB be x
  The delay at 5/6th of the original speed for a distance of (x-60)kms is 1hr 12mins
  The delay at 5/6th of the original speed for a distance of (x-120)kms (if the accident took place 60 kms further i.e 60+60 kms from Amster) is 1hr
  Therefore, at 5/6th of the original speed the delay is 12 mins per 60kms
  Therefore, for a delay of 1hr 12 mins the distance covered is 60*(72mins/12mins)
  = 60*6 =360kms
  total distance bet stns is 360+60kms (60kms travelled before accident)
  =420kms
• 11 years agoHelpfull: Yes(1) No(1)
• Didn't know speed was asked,
  Let T1,S1 & D1 be the original time, speed and distance
  T2, S2& D2 be the time, speed and distance after accident
  D1=D2=60kms
  T2=T1+12mins
  S2=5S1/6
  s=d/t
  60=S1*T1=S2*T2
  S1*T1=(T1+12)*5S1/6
  T1=5T1/6 + 10
  T1/6=10
  T1=60MINS=1hr
  S1=D1/T1=60/1
  =60kmph
• 11 years agoHelpfull: Yes(1) No(0)