a circle whose area is 2 pie a rectangle inside the circle then find the parameter of that rectangle

Area=2/pie
so ,
pie*r^2=2/pie (r=radius of the circle)
=>r^2=2/pie^2
=>r=>sqrt(2)/pie
so , diameter of the circle=2*sqrt(2)/pie
for the rectangles whose diagonal is diameter of the circle, following equation is applicable
l^2+b^2=(2*sqrt(2)/pie)^2
=>l^2+b^2=8/pie^2
Apart from this many rectangles are possible. for them parameters will be different!
11 years agoHelpfull: Yes(5) No(6)
Many rectangle are possible in circle of area 2/pie and hence radius (sqrt2)/Pie.
11 years agoHelpfull: Yes(4) No(2)
area of circle = pie*r^2
2/pie = pie*r^2;
therefore r = underroot2/pie;
since rectangle is inside the circle, therefore rectangle diagonal made a righ angle triangle suppose abc where ab and bc are lenght and base of a triangle and also equal to radius.
hence ab and bc = underrot2/pie.
hence ac^2 = underrot2/pie^2 + underrot2/pie^2 ;
ac = 2/pie.
where ac is the lenght of a rectangle.
the parameter of rectangle is 4 times of ac = 4*2/pie = 8/pie
11 years agoHelpfull: Yes(2) No(6)
@ sambhit Ghosh can u explain ur answer?
10 years agoHelpfull: Yes(1) No(0)
ans should be 6/pi
10 years agoHelpfull: Yes(0) No(3)

a circle whose area is 2/pie.a rectangle inside the circle.then find the parameter of that rectangle.