Elitmus
Exam
find the number of possible integral value of X.
for which this(3*X+7)^2/(X+4) give the integer value.
options:
a. 2 b. 4 c. 6 d. infinte
Read Solution (Total 6)
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- after dividing the no. we get 25/X+4 as remainder.
possible no: -29,21,-9,-5,-3,1 - 11 years agoHelpfull: Yes(27) No(3)
- (3X+7)^2/(X+4)=(3X+7)*[(3X+7)/(X+4)]=I*II
Part I will be integer for every integral value of X,then consider Part II
we can modify it as (3X+12-5)/(X+4)=[(3X+12)/(X+4)]-[5/(X+4)]=3-[5/(X+4)]
so 5/(X+4) would be an integer for X value 1 and -9.
So the answer will be 2 - 11 years agoHelpfull: Yes(22) No(6)
- I got 3 values of x.
x= -3,1,21 for positive integer values of (3*X+7)^2/(X+4). - 11 years agoHelpfull: Yes(4) No(5)
- I got 3 values of x.
x= -5,1,21 for positive integer values of (3*X+7)^2/(X+4). - 11 years agoHelpfull: Yes(2) No(3)
- wht is d rght answer?
- 11 years agoHelpfull: Yes(1) No(0)
- @bhi,,
how did you get that abhi?
could you explain me some what clear?
- 11 years agoHelpfull: Yes(0) No(0)
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