in a triangle ABC angle a is the smallest one. A+7B=112 find the range of value c

• A+7B=112
  =>7B=112-A:So it means 112-A should be divisible by 7 and the values of A that satisfies this condition are 0,7,14......
  So 1st take A as 7,then B=(112-7)/7=15,C=180-(7+15)=158
  then take A as 14,then B=14 and C=180-28=152
  Here A=B,it does not satisfy the condition that A is the smallest one.So the answer would be A=7,B=15,C=158.
• 11 years agoHelpfull: Yes(31) No(3)
• When A=0 ( approx), B= 16 deg (approx); C= 164 deg
  when A=Approx B= approx14; A+B=28 deg (approx); C= 180-28=152 deg
  
  so range of C is (152,164)
• 11 years agoHelpfull: Yes(26) No(10)
• @ Satyaranjan,
  
  There is no condition that Angles should be integer only.
  A can have values from 0.00000000001 to 13.999999999999
  and accordingly C will be in range of 152.00000000001 to 163.999999999999
  or (152,164) as explained by Karan.
  Have fun.
• 11 years agoHelpfull: Yes(11) No(1)
• A+7B=112
  it is clear that A=14, then it becomes A>=B, but A is smallest angle)
  so, range of A is 0.0001 to 13.9999 ( I am taking upto 4 decimal places)
  so, range of B becomes 14 to 16 ( after rounding off to 4 decimal places)
  so, range of C becomes 152 to 164 ( after rounding off to 4 decimal places)
  finally we can say
  0.0001
• 11 years agoHelpfull: Yes(1) No(2)
• A+7B=112
  neglect A(Bcoz a is small)
  7B=112 => B=16
  In /_ABC total degrees 180...
  So,
  C angle in range 16
• 11 years agoHelpfull: Yes(0) No(9)