how many 4 digit numbers divisible by 5 formed from the number 0,1,2,3,4,5,6 and 6?

answer=249

• In order to be divisible by 5, the last digit can only be 0 or 5.
  
  Case 1.... Only one 6 is used and when 0 comes last = 6*5*4=120
  Case 2......Only one 6 is used and when 5 comes last = 5*5*4=100 ways
  Case 3....Two 6s are used and when 0 comes last = 3*5=15 ways
  Case 4..Two 6s are used and when 5 comes last and 4th digit is zero = 2 cases (like 6605 and 6065 only).
  Case 5..Two 6s are used and when 5 comes last and 4th digit is not zero = 3*4=12
  
  so total possible numbers are 120+100+15+2+12= 249
• 11 years agoHelpfull: Yes(23) No(19)
• Repetition is not mentioned in the question.
  Hence total 4 digit numbers div by 5 will be = 6*7*7*2= 588
• 11 years agoHelpfull: Yes(5) No(2)
• well explained, Dipin. Thanks a lot.
• 11 years agoHelpfull: Yes(1) No(1)
• thanx dipin
  
• 11 years agoHelpfull: Yes(0) No(2)
• @dipin
  if there is no restriction,,,,,,then
  y u hv taken only 6 two times???
• 11 years agoHelpfull: Yes(0) No(0)