cost of articles ratio is in 3:2,on the first there is 40% loss and on the second 30% gain,what is the overall percentage of loss

• 12% loss
  Let the cost of first & second articles are 3x & 2x, total cost=5x
  Selling price of first & second articles will be 0.6*3x=1.8x & 1.3*2x=2.6x
  Total selling price=1.8x+2.6x=4.4x
  % of selling price to the cost price=4.4x*100/5x=88, So loss=12%
• 11 years agoHelpfull: Yes(7) No(0)
• consider A and B
  Cost of A= 3rs
  cost of B = 2 rs
  30%loss of A is = 3-(3*0.4) = 1.2 --->(1)
  20% of gain of B is = 2 + (2*0.3) = 2.6----> (2)
  
  add (1) and(2) we get
  total = 4.4
  total percentage loss is 100 - [(4.4/5)*100] = 12%
• 11 years agoHelpfull: Yes(5) No(1)
• let cost of first article be 300/- and that of second be 200/-
  40% loss on first means S.P=60%of 300 = 180
  30% gain on second means S.P=130% of 200 = 260
  overall loss=(300+200)-(180+260) = 60/-
  loss% = 60/500*100=12%
  
• 11 years agoHelpfull: Yes(3) No(0)
• c.p=3x+2x=5x
  s.p=60/100(3x)+130/100(2x)=4.4x
  loss=0.6x
  loss%=0.6/5*100=12%
• 11 years agoHelpfull: Yes(1) No(0)
• ans is 12%.
  let price be 3x and 2x.
  total cp=5x.
  sp of 1st item=3x-(0.4*3x)=1.88x
  sp of 2nd item=2x+(0.3*2x)=2.6x
  total sp=(1.88+2.6)x=4.4x
  loss=cp-sp=(5-4.4)x=0.6x
  loss %=(0.6x/5x)*100=12%.
• 11 years agoHelpfull: Yes(1) No(0)