Cost of articles is in ratio 3:2 on the first,there is 40% loss and on the second ,30% gain.What is overall percentage of loss?

• 12%
  
  {(3*40) - (2*30)}/5
  =60/5
  =12%
• 11 years agoHelpfull: Yes(12) No(0)
• let the cost of articles be 3x and 2x
  40%loss in the first one means that sell price of first is 1.8x
  30%gain in the second one means that sell price of second is 2.6x
  
  total selling price=(1.8x+2.6x)=4.4x
  given cost price = (3x+2x)=5x
  so loss= (4.4-5)x= 0.6x
  loss percentage= (0.6x/5x)*100=12%
• 11 years agoHelpfull: Yes(8) No(0)
• 3:2
  let us assume:
  300:200
  40% loss on 300 -> 300*(40/100)=>120 loss
  30% gain on 200 -> 200*(30/100)=>60 gain
  overall loss is 120-60 => 60
  total is 500
  60 is 12 percent on 500
  
  so the answer is 12%
• 11 years agoHelpfull: Yes(8) No(0)
• c.p=3x+2x=5x
  s.p=60/100(3x)+130/100(2x)=4.4x
  loss=0.6x
  loss%=0.6/5*100=12%
• 11 years agoHelpfull: Yes(2) No(0)
• total selling price=(1.8x+2.6x)=4.4x
  given cost price = (3x+2x)=5x
  so loss= (4.4-5)x= 0.6x
  loss percentage= (0.6x/5x)*100=12%
• 11 years agoHelpfull: Yes(1) No(0)
• c.p=3x+2x=5x
  s.p=60/100(3x)+130/100(2x)=4.4x
  loss=0.6x
  loss%=0.6/5*100=12%
• 11 years agoHelpfull: Yes(1) No(0)
• Let the cost of article 30 and 20
  40% Loss in first article 30/100x40=12
  30% Loss in Second article 20/100x30=6
  So over all 12-6 = Rs.6 loss
  Then over all % loss is 6/50x100 = 12 %
  
• 11 years agoHelpfull: Yes(0) No(0)