Elitmus
Exam
how many set of consiqutive no less then 1000 whos sum is divisible by 10 ? Dnt remember exactly
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- Ans: 0
No two consecutive nos have a sum which is divisible by 10. - 11 years agoHelpfull: Yes(7) No(17)
- 99 sets below than 1000 that is divisible by 10
- 11 years agoHelpfull: Yes(1) No(1)
- If the question is 3 consecutive sets:then
9+10+11
19+20+21
29+30+31
.
.so on
989+990+991
total number of sets=99
like this for 5 consecutive number
8,9,10,11,12
18,19,20,21,22
28,29,30,31,32
...
...
...
988,989,990,991,992
hence total number of sets=99
for 7 and 9 consecutive numbers each 99 sets - 8 years agoHelpfull: Yes(1) No(0)
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