find the remainder when 2^15 is divided by 5.

• 2^15= 2^10*2^5 = 1024*32
  so last digit will be 8.
  remainder will be 3 when 8 is divided by 5 or when 2^15 is divided by 5.
• 11 years agoHelpfull: Yes(11) No(3)
• 2^15=(2^5)^3=32^5=....8%5=3
  ans:3
• 11 years agoHelpfull: Yes(9) No(3)
• 3 because 2^5^3=32^3 by cubing 2 we get 8 at the end so when we divide them with 5 we get 3 as remainder
• 11 years agoHelpfull: Yes(2) No(1)
• series goes like this
  2(2^1), 4, 8(2^3), 16, 32(2^5)
  so 2^15= (2^5)^3
  = (last digit of32- 2)^3
  = (2)^3 = 8 divided by 5 so remainder will b 3
• 11 years agoHelpfull: Yes(1) No(0)