meena got married 6 years ago.today her age is 8/3 times of marriage.her son age is 1/6 times her age.her son age is

• Is the data correct ? Pls check.
  
  if age of meena at marriage was x years, then
  x*8/3 -x=6
  x= 6*3/5 = 18/5 yrs
  her present age = (8/3)*(18/5)= 48/5 yrs
  son's age = (48/5)*(1/6)= 8/5 yrs
  
  
  If meena was married 60 years ago, then their present ages will be 96 yrs and 16 yrs.
  
  Pls check data.
• 11 years agoHelpfull: Yes(10) No(1)
• Let the meena's present age be x years.
  so According to the given condition
  x = 8/3*(x-6)
  Present age(x) = 8/3 times of meena's marrriage age(x-6)
  solving above equation
  x = 48/5 years(Her present age)
  Her son's age = (1/6)*(48/5) = 8/5 years
• 11 years agoHelpfull: Yes(4) No(6)
• let preset age be X
  x/(x-6)=8/3
  x=48/5
  hence sons age 48/(5*6)=8/5
• 10 years agoHelpfull: Yes(2) No(0)