How many 4 digits no are divisible by 25 among the digits 0,1,2,3,4,5,6,7 with no digit being repeated

• 80
  last 2 digit can be 25 , 50 and 75
  so for _ _ 2 5 arrangement can be 5*5 because 0 cannot come on first position 25
  simillarly for _ _ 7 5 25
  and for _ _ 5 0 6 *5 = 30
  so 25+25+30=80
  
• 11 years agoHelpfull: Yes(31) No(3)
• i think it is 84,,
  _ _ 25
  or
  _ _ 50
  
  or
  _ _ 75
  
  case 1: _ _ 25
  possibility for 2st digit=6
  possibility for 1st digit=4(except 0)
  6*4=24
  same for _ _ 75=24
  case 2: _ _ 50
  possibility for 2nd digit=6
  possibility for 1st digit=6
  6*6=36
  total=2(24)+36=84
• 11 years agoHelpfull: Yes(2) No(2)
• --25
  --50
  --75
  case 1:--25
  when 1 is at thousand place no of ways is 5
  similarly 2 is not considered as the digits will be repeated
  when 3,4,6,7 is used again there i 5 ways so total 25 ways
  case 2:--50
  there is 30 ways
  case 3:--75
  there is 25 way so total ways is 25+25+30=80
• 11 years agoHelpfull: Yes(2) No(1)
• 5! 4! 2 because when the number has to be divisible by 25 last two numbers must be 5 0 so last two digits are 5 and 0 so remaining 5 num are placed in 5! ways and in second digit in 4! ways.
• 11 years agoHelpfull: Yes(0) No(0)
• 7c3 * 3! * 2
  am i rite?
• 11 years agoHelpfull: Yes(0) No(2)