We know that after nos n>4 the factorial for every n has trailing zeroes . We denote trailing zeroes by k. What value of k among 1 to 22 is not possible.

• sry there are total 3 values which are possible 5,11,17 will explain it later
• 11 years agoHelpfull: Yes(4) No(0)
• ohhh okk shweta 3 values not possilbe
  firstly 5
  for 4 values 20/5 =4(no of zeros
  but for 5 values 25/5 + 25/25 =5+1 =6(5 values are never possible)
  2ndly, 10 values 45/5+ 45/25 =9+1=10
  but for 11 values 50/5 + 50/25=10+2=12(hence 11 values are never possible
  For 16 values 70/5 + 70/25 =14+2 =16
  But for 17 values 75/5 +75/25 =15+3 =18(hence 17 values are not possible )
  so answer is 3 values (5,11,17)
• 11 years agoHelpfull: Yes(3) No(3)
• 5 and 16 is not possible
• 11 years agoHelpfull: Yes(0) No(1)
• ms.diksha pls explain d answer
  
• 11 years agoHelpfull: Yes(0) No(0)
• acc to my cal 5,11,16
• 11 years agoHelpfull: Yes(0) No(1)
• @sumit thnx bt pls explain?
  
• 11 years agoHelpfull: Yes(0) No(0)
• can anyone tell me another way of solving this question?
• 11 years agoHelpfull: Yes(0) No(0)
• 5,11,12,18
• 11 years agoHelpfull: Yes(0) No(0)