What is the minimum value of x possible if |x|=|x-1|+|x-2|
Options a)1 b)2 C)0,d)6

• (a)
  use hit and trial method,
  if x=0,then |0|=|0-1|+|0-2| => |0|=|-1|+|-2|
  => |0|=1+2 => 0=3 which is absurd
  in the same way put x=1
  |1|=|1-1|+|1-2| => |1|=|0|+|-1|
  => |1|=0+1 => 1=1 which is possible
  in the same way put x=2
  |2|=|2-1+|2-2| =>|2|=|1|+|0
  => |2|=|1| which is absurd
  in the same way put x=3
  |3|=|3-1|+|3-2| => |3|=|2|+|1|
  => |3|=2+1 => 3=3 which is possible
  so minimum value will be 1.
• 11 years agoHelpfull: Yes(25) No(0)
• Ans a.
  min{x|at x = 1
• 11 years agoHelpfull: Yes(0) No(0)
• |x|=|x-1|+|x-2|
  as we know that for real x |x| will be -x and +x
  so...
  first..
  x=x-1+x-2
  ===>> x=3;
  and second
  -x=-x+1-x+2
  ===>> x=3
  so only one value is possible i.e. 3..
  so ans will be 1
• 11 years agoHelpfull: Yes(0) No(1)