In an opinion poll 78% of those asked were in the favour of atleast one of the three sports persons to be included in the commonwealth organizing commitee Saina, Dhoni and Anand. 50% of those asked favoured Saina, 30% favoured Dhoni 20% favored Anand.If 5% of those asked favoured all of them,what percentage of those asked favoured atleast one person ??
Options
A)61
B)56
C)51
D)22

• Let x% be in favour of A and B
  y% be in favour of B and C
  z % be in favour of A and C
  
  => 78 - 5 - (x + y + z) = (50-5-x-z) + (30-5-x-y) + (20-5-y-z)
  => (x + y + z) = 12%
  
  => (78 - (x+y+z)-5) = 61%
• 10 years agoHelpfull: Yes(35) No(4)
• comes out to be 61 for exactly one.
  
• 11 years agoHelpfull: Yes(7) No(0)
• opinion poll 78%
  let X% for A&B
  Y% for B&C
  Z% for C&A
  78-5-(X+Y+Z)=(50-5-X-Z) + (30-5-x-y) + (20-5-y-z)
  => 73 -X-Y-Z=100-15-2X-2Y-2Z
  => (X+Y+Z)=12%
  78-5-12=61% ans
• 8 years agoHelpfull: Yes(7) No(0)
• 61 for exactly one person
  
  
• 11 years agoHelpfull: Yes(3) No(1)
• let total members be 100
  78% of 100 is 78
  
  raina=50%of 78=39
  dhoni=30%of 78~23
  anand=20%of 78~16
  all 5%of 78 all=3.4~3
  
  use venn diagram dude
  
  so atleast one person=only raina+only dhoni+only anand+raina&&dhoni&&anand
  =raina-all+dhoni-all+anand-all+all
  =39-3+23-3+16-3
  =36+20+13=69
  69*100/78=88.8
• 11 years agoHelpfull: Yes(2) No(13)
• 61%
  
  5% were in favour of all
  Let x% be in favour of A and B
  y% be in favour of B and C
  z % be in favour of A and C
  
  => 78 + 5 - (x + y + z) = (50+5-x-z) + (30+5-x-y) + (20+5-y-z)
  => (x + y + z) = 32%
  
  => (78 - (x+y+z)+5) = 51% favoured exactly one.
• 8 years agoHelpfull: Yes(1) No(0)
• In the last line it is exactly one person by this the answer is 56
• 11 years agoHelpfull: Yes(0) No(11)
• will u pls explain the answer....mr. sumit
• 11 years agoHelpfull: Yes(0) No(3)
• @sumit pls explain d answer?
  
• 11 years agoHelpfull: Yes(0) No(1)
• could anyone tell me the another way of solving this question?
  I am not getting this ways
• 10 years agoHelpfull: Yes(0) No(1)
• Let x% be in favour of A and B
  y% be in favour of B and C
  z % be in favour of A and C
  
  => 78 - 5 - (x + y + z) = (50-5-x-z) + (30-5-x-y) + (20-5-y-z)
  => (x + y + z) = 12%
  
  => (78 - (x+y+z)-5) = 61%
  Read more at http://www.m4maths.com/18476-In-an-opinion-poll-78-of-those-asked-were-in-the-favour-of-atleast-one-of-the-three-sports-persons.html#2cH2IsUPbhIZsrWs.99
• 8 years agoHelpfull: Yes(0) No(0)
• Abxjdjdheisisudh
• 1 year agoHelpfull: Yes(0) No(0)