how many 4 digits number can be formed by using set 0,1,2,3,4,5,6,7 which is divisible by 25 and repetition of digit is not allowed..

• if 25 is the last two numbers then the first number can be selected in 5 ways (1,3,4,6,7) and the second number can be selected in 5 ways (4 numbers from the set of numbers and 0 included . so total 5) so the total number of ways are 5*5=25....(1)
  similarly if 75 is the last two numbers then there 25 ways possible.....(2)
  if 50 is the last two numbers then the first number can be selected in 6 ways and the second number in 5 ways. so total wys = 6*5 =30 .....(3)
  hence the total possible ways are 25+25+30 = 80
• 11 years agoHelpfull: Yes(30) No(3)
• The correct answer is 80
• 11 years agoHelpfull: Yes(8) No(0)
• At the last two places 25, 50, 75 are possible.
  100th place can be filled by (8-2)= 6 different numbers.
  1000th place can have (8-3-1)= 4 because 0 can't be at 1000th place.
  total numbers will be = 4*6*3= 72
• 11 years agoHelpfull: Yes(1) No(14)
• I am also getting 72 Answer
  what is correct answer..??
  
• 11 years agoHelpfull: Yes(0) No(5)
• 72 is the correct answer
  
• 11 years agoHelpfull: Yes(0) No(5)
• __ __ 2 5= 5*5
  
  __ __ 5 0=6*5
  
  __ __ 7 5 = 5*5
  
  total =25+30+25= 80
• 7 years agoHelpfull: Yes(0) No(0)