ABCD is a rectangle and APD is a I soscele triangle. angle APD is 100` ,diagonal AC has the twice length than CD. AC cuts PD at X .then what is the angle AXP??
A) 70 B)80 C)90 D)100

• The answer is 70 degrees. TO explain we need to draw a figure and after drawing figure it can be clearly inferred
• 11 years agoHelpfull: Yes(5) No(1)
• 70
  in triangle APX
  /_ PAX+/_ AXP=80
  since any angle in a triangle must not be equal to zero
  so /_ PAX != 0
  and /_ AXP= 70
• 10 years agoHelpfull: Yes(4) No(3)
• i think this ques is practically impossible.If APD is 100 degrees and PAD is 90 degrees hoe can a triangle be formed???correct me if iam wrong
• 9 years agoHelpfull: Yes(4) No(3)
• 70 DEGREE
  
• 11 years agoHelpfull: Yes(1) No(0)
• plz explain
• 11 years agoHelpfull: Yes(0) No(0)
• draw rectangle naming ABCD
  APD IS A ISOS.. AND
• 11 years agoHelpfull: Yes(0) No(1)
• draw rectangle naming ABCD
  APD IS A ISOS.. AND
• 11 years agoHelpfull: Yes(0) No(2)
• Right @Akanksha..........I also think this question is not practically exist
• 9 years agoHelpfull: Yes(0) No(0)
• Your options are not correct
  
  Correct ans will be 60 degree
  It is not given in ur options but was there in elitmus question paper.
• 9 years agoHelpfull: Yes(0) No(0)
• Question is right you just have to draw the figure ans is 70 degree
  I am trying to explain I hope u ll get it.
  According the question triangle is Isocelles so one side is given 100 so another sud b 40 and 40.
  Now one more clue give that AC is twice of CD it means trang ACD is right angle having angle 30 60 and 90
  Now
  Angle PAD=PAC+CAD
  PAD is 40 and CAD IS 30 so PAC ll be 10
  Now in PXD 180-100-10=70
• 7 years agoHelpfull: Yes(0) No(1)