Elitmus
Exam
A N D
x O W N
___________
G D O N
C D D E
D U N U
___________
D A A M A N
Read Solution (Total 8)
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- brother i just have one doubt. is that CDDE or is it CODE. because if it is CODE then i am pretty sure i have the answer. it will be A=9,N=5,D=7,W=3,O=8,U=6,M=0 and E=1. so the question will be 957*835 = 799095 which is DAAMAN. please clarify if the product of W and AND is CDDE or CODE.
- 11 years agoHelpfull: Yes(9) No(7)
- guys, whats the trick for solving such questions? plzz explain..
- 11 years agoHelpfull: Yes(1) No(0)
- 1. basic trick is finding 5,6 or 1,9
2. 5*3=5(+10) 5*7=5(+30) 5*9=5(+40) & 6*2=2(+10) 6*4=4(+20) 6*8=8(+40)
suppose N=5,
D must be 3,7,9... nd O>5 then O*D=U & O*N +carry=N that implies O=8
then D=7.
A57*5=G785 => A=9 nd G=4
8+E=9 =>E=1
7+7+6=M => M=0
G+O+N+2(carry)= 9 then C+6+1(carry)=9 =>C=2....
finaly 957*8(W=3)5= 2871...
W=3.
- 11 years agoHelpfull: Yes(1) No(0)
- ya rahman. its CODE not CDDE.
- 11 years agoHelpfull: Yes(0) No(0)
- @rizwanur rahman can you explain this here??
- 11 years agoHelpfull: Yes(0) No(0)
- @rizwanur plz explain
- 11 years agoHelpfull: Yes(0) No(0)
- plz mail me elitmus question or any study material to my email id-ghoshsambit1990@gmail.com
- 11 years agoHelpfull: Yes(0) No(0)
- plzz explain the trick for solving cryptarithmetic prbs............
- 11 years agoHelpfull: Yes(0) No(0)
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