a train covered a certain distance at a uniform speed.if the train could have been 10 km/hr faster, it would have taken 2 hours less than the scheduled time. and if the train were slower by 10 km/hr, it would have taken 3 hours more then the scheduled time. the distance covered by the train is ?

• 600 km
  
  Let the scheduled distance travelled = d,
  time taken = d, uniform speed = s
  => d = st ----------(1)
  
  If s -> (s + 10) => t -> (t - 2)
  => d = (s + 10)*(t - 2)--------(2)
  => d = st + 10t - 2s - 20
  From (1) => 5t - s = 10 ------(3)
  
  If s -> (s - 10) => t -> (t + 3)
  => d = (s - 10)*(t + 3)--------(4)
  
  (2)/(4) => (s + 10)*(t - 2) = (s - 10)*(t + 3)
  => 10t - 2s - 20 = -10t + 3s - 30
  => 20t - 5s = -10
  => s - 4t = 2 ---------(5)
  
  From (3) and (5),
  s = 50 km/hr , t = 12 hrs
  
  => d = st = 600 km
• 11 years agoHelpfull: Yes(4) No(1)