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Numerical Ability
Permutation and Combination
in group of 15 ,7 studied latin 8 studied greek 3 not studied either how many of these both studied latin n greek
Read Solution (Total 6)
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- In a group of 15, 3 have not studied either.
In the group of 12 who have studied at least one, 7 have studied Latin and 8 have studied Greek.
7+8=15, which is 3 larger than 12.
Therefore, 3 students studied both.
Let's check our work:
Not studied either: 3
Studied both: 3
Studied just Latin: 7-3=4
Studied just Greek: 8-3=5
3+3+4+5=15 - 11 years agoHelpfull: Yes(48) No(8)
- USING VENN DIAGRAM
now we have some equations
(i) A + x + B + 3 = 15
(ii) A + x= 7
(iii) B + x = 8
adding (ii) and (iii), we get
(iv) A + B + 2x = 15
substituting (i) and (iv) we get
A + x + B + 3 = A + B + 2x
subtracting A and B we get
x + 3 = 2x
subtract x to get
x = 3.
3 studied both Latin and Greek - 11 years agoHelpfull: Yes(23) No(0)
- 3 studied both.
Bcoz 15-3=12 these are the people studied.
7+8=15.
within 12 people how could we get 15 people. so 3 people studied both.
- 11 years agoHelpfull: Yes(12) No(1)
- 192...
( ) ( ) ( )
8 ways * 6 ways * 4 ways
from 8 members-8 ways
we have 7 now but one in 7 is its spouse-6 ways
now we have 5 but one is spouse of it-4 ways - 11 years agoHelpfull: Yes(3) No(4)
- let 'x' who has both studied latin and greek
then
7+8+3-x=15
x=18-15
x=3
ans 3 - 11 years agoHelpfull: Yes(1) No(0)
- First, draw a venn diagram with 2 circles. draw lines in each oval area and a line outside on the right side. These four lines need four numbers.
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step 1 - place "A" on the first line, "x" on the second line, "B" on the third line and "3" on the outside fourth line.
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step 2 - now we have some equations
(i) A + x + B + 3 = 15
(ii) A + x= 7
(iii) B + x = 8
adding (ii) and (iii), we get
(iv) A + B + 2x = 15
substituting (i) and (iv) we get
A + x + B + 3 = A + B + 2x
subtracting A and B we get
x + 3 = 2x
subtract x to get
x = 3.
3 studied both Latin and Greek - 11 years agoHelpfull: Yes(0) No(0)
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