red,green,blue balls r there,108 balls are placed.there are twice as many ball in green n red box combined as there are in blue box and twice as many in blue box as there r in red box how many balls r there in green boxs

• Let R, G and B represent the number of balls in red, green and blue boxes respectively.
  
  Then, .
  
  R + G + B = 108 ...(i),
  
  G + R = 2B ...(ii)
  
  B = 2R ...(iii)
  
  From (ii) and (iii), we have G + R = 2x 2R = 4R or G = 3R.
  
  Putting G = 3R and B = 2R in (i), we get:
  
  R + 3R + 2R = 108 6R = 108 R = 18.
  
  Therefore Number of balls in green box = G = 3R = (3 x 18) = 54.
• 10 years agoHelpfull: Yes(85) No(8)
• 2(G+R)=B
  2B=R
  G+R+B=108
  G+R+2(G+R)=108
  3G+3R=108
  B=36ans
• 7 years agoHelpfull: Yes(0) No(0)