a n b throw a dice probability that a s throw is not greater than b

A's throw throw could be greater than B by following ways
2,1 3,2 3,1 4,3 4,2 4,1 5,4 5,3 5,2 5,1 6,5, 6,4, 6,3 6,2, 6,1
So 15 possibles out comes
Probability is 15/36 or 5/12
Probability of failure 1-p
so 1-5/12
= 7/12
11 years agoHelpfull: Yes(3) No(6)
A's throw throw could be greater than B by following ways
2,1 3,2 3,1 4,3 4,2 4,1 5,4 5,3 5,2 5,1 6,5, 6,4, 6,3 6,2, 6,1
So 15 possibles out comes
Probability is 15/36 or 5/12
Probability of failure 1-p
so 1-5/12
= 7/12
11 years agoHelpfull: Yes(2) No(4)
total no .of possibilities =36
among them 6 pairs are equal and remaining combinations = 30
among them half have first one greater than second = 15
probability is=15/36=5/12
11 years agoHelpfull: Yes(1) No(1)
If a's value is 1 means there may be a chance of b's value is greater than a's like 2,3,4,5,6
Like this the probability is 15
11 years agoHelpfull: Yes(0) No(5)
sample space=6*6=36
now favorable cases:
1)when b's dice show 6,a's dice has 5 chances for a
11 years agoHelpfull: Yes(0) No(1)
a
11 years agoHelpfull: Yes(0) No(0)
we are throughing 6 dice total outputs 6^2=36
15 are a>b; 15 are a
11 years agoHelpfull: Yes(0) No(0)

a n b throw a dice probability that a's throw is not greater than b