Anoop managed to draw 3 circles of equal radii with their centres on the diagonal of a square such that the two extreme circles touches two sides of the square and each middle circles touches two circles on either side.find the ratio of the side of the square to radius of the circles.you may assume square root of 2 is 1.4.

• Ans is 4.2
  let a is the side of squre , and d be the diagonal and r is radius of circle
  then, 6r=d;
  d=a*squrt2
  thrfore: a=d/squr(2); thn a/r=(d*6)/(sqrt(2)*d)
  hence a/r=3*sqrt(2)=4.2
• 11 years agoHelpfull: Yes(11) No(1)
• assume radius of circle=r
  dide of square=a
  then by geometry of the circle and square we get a=2*sqrt(2)*r=>2.8
• 11 years agoHelpfull: Yes(2) No(3)
• The extreme circles will have radius perpendicular to sides..so the part of diagonal till the centre of cirlce will be sqrt(2)r [Make diagram and it will be clear]..now remaining portion is r , 5 more circles will contribute 10r and last circle will contribute sqrt(2)r + r.
  
  total 12r + 2sqrt(2)r = sqrt(2) side
  
  so ratio of r:s = 1/2+6sqrt(2)
• 11 years agoHelpfull: Yes(0) No(2)
• can you find the ratio.. what will be... (options are of this question)
  a. 9.10:1
  b. 6.20:1
  c. 4.80:1
  d. 7.10:1
• 11 years agoHelpfull: Yes(0) No(2)
• Let r and a be the radius and side of circle and square
  sum of diameter of three circles are = (2)^1/2a
  r = ((2)^1/2)a/3*2
  therefore,
  a:r = 2.6 or, 13:5.
• 11 years agoHelpfull: Yes(0) No(1)
• let, side of square='a'
  radius of circle='r'
  then, we have a^2+a^2=(4r)^2 => a:r= 2 (2)^0.5= 2*1.4= 2.8
• 11 years agoHelpfull: Yes(0) No(0)
• @neetu gokhe..according to me ans is (c)4.80:1 beacause...let radius of circle be x and size of square be a ...as we know that two circle touches square...hence diagonal of square will be a*sqrt2=2*r*sqrt2+4*r....hence solving this you will get a:r=4.80:1
• 11 years agoHelpfull: Yes(0) No(0)