100^x (log 4 base x - log root2 base x )..Find Min and max values.
a. 0,infinity b. -infinity, infinity c. infinity,-infinity d.none

• value would always be positive value as log4basex-logroot2basex cant be negative
  so answer would be 0 to infinity
• 11 years agoHelpfull: Yes(10) No(0)
• the answer will be (c).....
  check the value for x=.5 it comes -ve
• 11 years agoHelpfull: Yes(2) No(4)
• 0 and infinity
• 11 years agoHelpfull: Yes(2) No(0)
• 100^x(log4 base x - log root2 base x )
  (log4 base x - log root2 base x ) = (2log2 base x - (1/2)log2 base x )
  = (3/2)(log2 base x)
  = 3/(2 * logx base 2)
  so resultent = ((100^x)*3)/(2*logx base 2)
  if x =1 then resultent = ((100^x)*3)/0 = infinity
  so max value is infinity
  
• 11 years agoHelpfull: Yes(1) No(0)