Sub prime numbers X,Y,Z where, Sub prime num means p+1. p= prime number. X>Y>Z>100. Which would be the closet value of (XYZ) ??
a. XY(Z-1) b,c,d i am not able to remember it right now.

• ans : xy(z-1) and xy(z+1)
  suppose three prinme num's > 100 are 101,103,107
  sub prime num's are 102,104,108
  x>y>z so x=108,y=104,z=102
  so xyz = 108104102
  so the closest values to xyz are xy(z-1) = 108104101 and xy(z+1) = 108104103
• 11 years agoHelpfull: Yes(17) No(6)
• it will be (x-1)yz or (x+1)yz because as we sub or add in higher num it won't effect as much as in case of lower num. take an example as x=6,y=4 &z=2
• 11 years agoHelpfull: Yes(7) No(3)
• (x-1)yz is the ans
• 10 years agoHelpfull: Yes(3) No(0)
• will be xy(z-1) only..
  
• 11 years agoHelpfull: Yes(1) No(3)
• some1 plzzz give the soln of this problem? what is closet value? i am not able to understand the question?
• 11 years agoHelpfull: Yes(1) No(0)
• @vijya singh adhikari -> dont be oversmart...you simply say answer
  can you able to explain what is the correct solution? and how you reached that answer?
• 9 years agoHelpfull: Yes(1) No(0)
• please explain it clearly..pls..
  
• 11 years agoHelpfull: Yes(0) No(0)
• xy(z-1) is ans
• 10 years agoHelpfull: Yes(0) No(1)