What will be remainder when (6767 + 67) is divided by 68 ?

• when [(a)^a+a]/a+1 in case of even number i.e [(2)^2+2]/3 remainder is 0.but when odd
  number divided it leave remainder (a-1). i.e [(3)^3+3]/4 remainder is 2 i.e (3-1).
  
  so when [(67)^67+67]/68 leave remainder (a-1) (67-1)=66
  
  answer is 66
• 10 years agoHelpfull: Yes(46) No(4)
• 6767+67=6834, when 6834/68 reminder will be 34.
• 10 years agoHelpfull: Yes(12) No(1)
• sorry the question is :
  What will be remainder when (67^67 + 67) is divided by 68 ?
• 10 years agoHelpfull: Yes(6) No(1)
• (6800-33+68-1)/68 gives reminder of 68-33-1=34
• 10 years agoHelpfull: Yes(5) No(0)
• the remainder will be 34
  
• 10 years agoHelpfull: Yes(1) No(0)
• ans is 66
  given 67^67+67/68
  so (-1)^67+67/68
  -1+67/68
  66/68
  so answer is: 66
• 10 years agoHelpfull: Yes(1) No(0)
• (67*67+67)/68=67
• 10 years agoHelpfull: Yes(0) No(3)
• (67^67+67) /68
  =(67^68)/68=
  ((68-1)^68 )/68
  Now,(x-1)^n/x.
  Gives remainder as 1 if x is even integer
  So ans is 1
• 10 years agoHelpfull: Yes(0) No(3)
• (4489+67)/68=67
• 10 years agoHelpfull: Yes(0) No(1)
• remainder=105
• 10 years agoHelpfull: Yes(0) No(4)
• 67(67+1)/68=67
• 10 years agoHelpfull: Yes(0) No(0)
• 1, because 6834%68=1
• 10 years agoHelpfull: Yes(0) No(0)