If the length of the rectangle is decreased by 4 and breath is increased by 3.then it becomes square whose areas are equal to that of rectangle. What is the perimeter of the original rectangle…

• 50
  If 'L' be the length and 'B' be the breadth of the rectangle, then decreasing the length and increasing the breadth we get,
  L=L-4; B=B+3
  So, it became Square. L-4=B+3 or L-B=7.......(1)
  Area of a Square= (L-4)^2= LxB or L^2 +16 -8L= LxB
  or L^2-LxB +16 -8L=0 or L(L-B)+16 -8L=0
  or L(7) +16 -8L=0.....from equtn (1)
  or 7L-8L +16=0
  or L= 16
  then B=9
  Perimeter of Rectangle 2(L+B)=50
  
• 10 years agoHelpfull: Yes(4) No(1)
• 144..
  by the given question we can form 2 eqs
  let 'L' be the length n 'B' be the breadth
  3L-4B=12
  L-B=7
  by solving we get L=16,B=9
  so the perimeter is 16*9=144
  (NOTE:we can also cross check..in the question it was given dat we length decreased by 4 and breadth increased by 3 then it forms a SQUARE
  L=16-4=12 B=9+3=12)
• 13 years agoHelpfull: Yes(1) No(3)