Infosys
Company
Numerical Ability
Permutation and Combination
There are 5 questions in each of the two sections. Three questions must be attempt for passing the exam how many ways a student will choose the questions…
Read Solution (Total 5)
-
- ANS: 120
Each section there are 5 questions so totally there are 10 questions
and 3 must be attempted so 10C3= 720/6 = 120
- 10 years agoHelpfull: Yes(3) No(0)
- 2(5C3+5C2.5C1)
- 13 years agoHelpfull: Yes(2) No(2)
- 120........
- 13 years agoHelpfull: Yes(0) No(0)
- there is two section and each section have 5 question...so total number of question is 10..and in which we have to attempt three question for pass...so 10C3 ie..720/6=120.
- 9 years agoHelpfull: Yes(0) No(0)
- there is two ways to choose no. of question from each section i.e. (1,2) and (2,1)
5C1 x 5C2 + 5C2 x 5C1 = 5 x 10 + 10 x 5 = 50 + 50 = 100
I hope it is correct - 6 years agoHelpfull: Yes(0) No(1)
Infosys Other Question