Derek throws three dice in a special game. If it knows that he needs 15 or higher in this throw to win, then find the chance of his winning the game.

A.5/54

B.17/216
C.13/216
D.15/216

• THINK THROUGH BEFORE TAKE CHOICE..ULTIMATE ANSWER WILL BE ALWAYS HIGHER IN PROBABILITY..
  
  TO WIN THE GAME HE HAVE TO GET 15 OR HIGHER (ie:16,17,18)
  
  SO CALCULATE CHOICES FOR THE NUMBERS 15,16,17,18.
  
  15=555 456 465 546 564 645 654 366 636 663
  16=466 646 664 556 565 655
  17=665 656 566
  18=666
  
  TOTAL=20
  TOTAL WAYS WHILE THROWING 3 DICES: 6*6*6=216
  
  SO CHANCE OF GETTING 15 OR HIGHER WILL BE AS FOLLOWS
  
  20/216=5/54.
  
  OPTION A IS RIGHT ANSWER.
• 11 years agoHelpfull: Yes(40) No(1)
• option a is the right answer 5/54 (5,4,6)(15) can be arranged in 6 ways
  (5,5,6)(16) can be arranged in 3 ways.(5,5,5)(15)in 1 way (6,6,6)(18) in 1 way (6,6,5)(17)in 3 ways (6,6,4)(16)in 3 ways (6,6,3)(15)in 3 ways totally 6+3+1+1+3+3+3=20 so propab is 20/(6^3)=20/216=5/54
• 11 years agoHelpfull: Yes(8) No(2)
• i think answer is 15/216.because there is (5,5,5)(4,5,6)(3,6,6)(6,4,5)(5,4,6)(6,3,6)(6,5,4)(6,6,3)(4,6,6)(5,6,6)(6,6,6)(6,4,6)(6,5,6)(6,6,4)(6,6,5)=15 ways
  so 15/216
• 11 years agoHelpfull: Yes(8) No(3)
• Here n(S)=6*6*6=216;
  E=Event of getting a total 15 or more than 15={555,556,565,566,564,546,456,465,466,366,666,665,656,664,646,654,645,663,636,655}
  =20
  that is 20/216=54/216
• 11 years agoHelpfull: Yes(5) No(0)
• THINK THROUGH BEFORE TAKE CHOICE..ULTIMATE ANSWER WILL BE ALWAYS HIGHER IN PROBABILITY..
  
  TO WIN THE GAME HE HAVE TO GET 15 OR HIGHER (ie:16,17,18)
  
  SO CALCULATE CHOICES FOR THE NUMBERS 15,16,17,18.
  
  15=555 456 465 546 564 645 654 366 636 663
  16=466 646 664 556 565 655
  17=665 656 566
  18=666
  
  TOTAL=20
  TOTAL WAYS WHILE THROWING 3 DICES: 6*6*6=216
  
  SO CHANCE OF GETTING 15 OR HIGHER WILL BE AS FOLLOWS
  
  20/216=5/54.
  
  OPTION A IS RIGHT ANSWER.
• 11 years agoHelpfull: Yes(4) No(0)
• to win the game Derek needs either 15,16,17 or 18 more than 18 not possible with 3 Dice(6+6+6=18).
  Dice1 Dice2 Dice3 Arrangement
  3 6 6 3!/2=3 (out of 3 , 2 are same that's divide by 2)
  4 5 6 3!=6(all are different)
  4 6 6 3!/2=3(same as in 3,6,6)
  5 5 5 1(all are same)
  5 5 6 3!/2=3
  5 6 6 3!/2=3
  6 6 6 1
  
  number of events=3+6+3+1+3+3+1=20
  probability=no. of events/total out comes
  =20/6^3
  =20/216=>5/54
  
• 11 years agoHelpfull: Yes(2) No(0)
• 366,466,465,456,566,565,556,546,564,666,665,656,646,664,636,663,654,645,655
  total 19 ways possible
  so required probability=19/216
  since no option is matching the answer should be NONE OF THESE. Correct me if i'm wrong
• 11 years agoHelpfull: Yes(1) No(1)
• b is the answer.if we throw a dice,there are 216 possibilities inorder to get 15 or higher (4,6,6)(6,4,4)(6,6,4)(...........like this v get the combination of 4,5,6 and 5,5,6 and 5,6,6 and 5,5,5, and 6,6,6
• 11 years agoHelpfull: Yes(1) No(0)
• 17/216
  555 556 565 655 666 645 546 564 456 465 654 663 366 636 664 466 646
• 11 years agoHelpfull: Yes(0) No(0)
• 17/216 coz (366 456 665 466 556) three times so total=15 +(555 666 ) one time so total of 17 ways
• 11 years agoHelpfull: Yes(0) No(0)
• 20 cases
  so 20/216
• 11 years agoHelpfull: Yes(0) No(0)
• 17/216
  (6,6,6),(5,5,5),(6,3,6)-all combination=3,(4,5,6)-all 6 combination=6,(6,6,5)-all three com.=3,(6,5,5)-all three com.=3.
  total com.=17
  no of total chances=216
  so, chances of winning=17/216
  
• 11 years agoHelpfull: Yes(0) No(2)
• its 17/216. expanding all the possibilities.
• 11 years agoHelpfull: Yes(0) No(3)