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City A's population is 68000, decreasing at a rate of 80 people per year. City B having population 42000 is increasing at a rate of 120 people per year. In how many years both the cities will have same population?
Read Solution (Total 4)
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- let no of years=x
then 68000-80*x=42000+120*x
ans=130 years - 13 years agoHelpfull: Yes(26) No(0)
- city A population = 68000
city B population = 42000
68000 decreasing at a rate 0f 80p = 42000 increasing at a rate of 120p
68000-80p=42000+120p
200p=26000
p=130years - 11 years agoHelpfull: Yes(8) No(0)
- at 100 years A's population is 60000 and B's population is 54000
at 130 years A's population is 57600 and B's population is 57600
so, at 130 years they have same population - 13 years agoHelpfull: Yes(0) No(3)
- AT 100 years A will hav 68000 and B will hav 54000
at 130 both will have 57600.
130 is the answer - 13 years agoHelpfull: Yes(0) No(1)
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