if x/y is a fraction and x/y+y/x=-1. Find X^3-Y^3 ?

• x/y+y/x = -1
  x^2+y^2/xy = -1
  x^2+y^2+xy = 0
  
  now x^3-y^3 = (x-y)(x^2+y^2+xy)
  = (x-y)*0 = 0 answer
• 11 years agoHelpfull: Yes(5) No(0)
• x/y + y/x =-1 => x^2 + y^2 = -xy
  now, x^3-y^3 = (x-y)(x^2+ y^2+ xy) =(x-y)(-xy+ xy)= 0
• 11 years agoHelpfull: Yes(0) No(0)