How many 1's are there in the binary form of 8*1024 + 3*64 + 3

• 8*1024 = 1000*10000000000 (the product will have one 1 only)
  3*64 = 11*1000000 (the product will contain two 1)
  3 = 11
  
  when added , we get five 1.
• 13 years agoHelpfull: Yes(15) No(12)
• total 4 ones
• 13 years agoHelpfull: Yes(12) No(7)
• five 1's is there. 8*1024+3*64+3=8387, then convert this value into binary 10000011000011
• 13 years agoHelpfull: Yes(9) No(7)
• Anikesh ma ke lode....
• 9 years agoHelpfull: Yes(4) No(4)
• five 1's. one 1 for 8*1024, two 1's for 3*64 and two 1's for 3.
• 13 years agoHelpfull: Yes(1) No(5)
• 8*1024+3*64+3=8387
  NOW BINARY
  8=1000
  3=0011
  8=1000
  7=0111
  
  so total 1's = 7
• 11 years agoHelpfull: Yes(1) No(16)
• to solve this arithmetic we get 8387 that is (10000011000011) in binary form. hence there are 5 1's in binary.
• 8 years agoHelpfull: Yes(0) No(0)
• 8*1024+3*64+3=8387
  NOW BINARY
  8=1000
  3=0011
  8=1000
  7=0111
  
  so total 1's
• 8 years agoHelpfull: Yes(0) No(0)
• 4 will be the answer
• 6 years agoHelpfull: Yes(0) No(0)