Product of three consecutive numbers are 7980.

Then the sum of these consecutive numbers would be ?

• let first no. as x,(x+1),(x+2).
  x*(x+1)*(x+2)=7980
  by solving this we get equation as,x=19;
• 10 years agoHelpfull: Yes(1) No(0)
• 7980=19*20*21
  19+20+21=60
• 10 years agoHelpfull: Yes(0) No(2)
• let no be x
  3 nos are x,x+1,x+2
  x*(x+1)*(x+2)=7980
  product==>19*20*21=7980
  sum==>19+20+21=60
• 7 years agoHelpfull: Yes(0) No(0)