reasoning
Maths Puzzle
Logical Reasoning
Mathematical Reasoning
A frog is at the bottom of a 30 meter well. Each day he summons enough energy for one 3 meter leap up the well. Exhausted, he then hangs there for the rest of the day. At night, while he is asleep, he slips 2 meters backwards. How many days does it take him to escape from the well?
Note: Assume after the first leap that his hind legs are exactly three meters up the well. His hind legs must clear the well for him to escape.
Read Solution (Total 2)
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- 28 days.
till 27 days,it will move 1 step forward and 2 step backward. hence it will cover 27 metres in 27 days. at 28th day , when it will move 3 metres upward,it will be outside the well and will have no need to slide backward. - 11 years agoHelpfull: Yes(18) No(1)
- Ans: 28th day (or 28 days)
Assume that if the frog correctly jump without any fall it will require only 10 days to come out of the Well, but here the twist is that for each frog slips 2 mts back.
i.e., 1st day = 3 mts lap, then remaining 27 mts to cover for the next day and each day only 1mts frog actually covers and 28th day he covered 27mts + 3mts. - 3 years agoHelpfull: Yes(1) No(0)
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