A student divided a number by 2/3 when he required to multiply by 3/2. Calculate the percentage of error in his result.

• suppose the no is 100
  first condition if it mistakenly divided the no by 2/3 ==>100/(2/3)==>150
  second condition the no should multiply by 3/2 ==> 100*3/2 ==> 150
  hence output should be 150 and mistakenly the output is 150
  so pecentage error is zero
• 12 years agoHelpfull: Yes(16) No(3)
• If expected answer was 100, then
  initial number = 100*3/2 =150.
  Final answer got by mistake = 150*3/2= 225.
  Error in result against expected result of 100 = 125.
  
  so % error = 125%
• 12 years agoHelpfull: Yes(10) No(19)
• there is no error in result because student unknownly multiply number by 3/2
  i.e x/2/3=x*3/2
• 12 years agoHelpfull: Yes(10) No(0)
• Student actually wants
  x*(3/2) = 3x/2
  
  but he did
  x/(2/3) = 3x/2
  
  So, 0% of error in the result.
• 11 years agoHelpfull: Yes(10) No(1)
• MULTIPLYING & DIVIDING BOTH ARE INVERSLY PRAPOTIONAL.SO THE ANS S 0%
• 8 years agoHelpfull: Yes(0) No(2)
• Let the number be x,
  On multiplying the number by 3/2, we get 3x/2 ........(1)
  On dividing the number by 2/3 i.e. x/(2/3) = 3x/2 ......(2)
  Hence we get same number in both cases (1) & (2), so there is no percentage error in the result.
• 3 years agoHelpfull: Yes(0) No(0)