Pipe A can fill in 20 minutes and Pipe B in 30 mins and Pipe C can empty the same

1 / (1/20+1/30-1/40) = 17 1/7
9 years agoHelpfull: Yes(1) No(0)
A = 20
B = 30
C = -40
LCM = 120
=> A = 6,TIMES
B = 4
C = -3
=> A+B-C = 7
TIME TAKEN TO FILL THE TANK = 120/7 MINS = 17 1/7 MINS
9 years agoHelpfull: Yes(1) No(0)
d.none of these
correct ans is 120/13..
9 years agoHelpfull: Yes(0) No(2)
Total time taken= 1/20 + 1/30 - 1/40 =7/120
time= 120/7 = 17 1/7
8 years agoHelpfull: Yes(0) No(0)
Lcm(20,30,40)=120->total work done
1 min work=
6+ 4 -3=7
120/7=17 1/7 mins
7 years agoHelpfull: Yes(0) No(0)
17 1/17mins is the correct answer
5 years agoHelpfull: Yes(0) No(0)
work=a+b-c
=1/20+1/30-1/40
=(6+4-3)/120
=7/120
time=inverse of work
=120/7
=17 1/7 mins
so,option a
5 years agoHelpfull: Yes(0) No(0)
total work=1/20+1/30-1/40=120/7
4 years agoHelpfull: Yes(0) No(0)
Pipe A can fill in 20 minutes and Pipe B in 30 mins and Pipe C can empty the same in 40 mins.If all of them work together, find the time taken to fill the tank
5 Months agoHelpfull: Yes(0) No(0)
minutes

Step-by-step explanation:

Pipe A can fill in 20 minutes

Pipe A can do work in 1 minute =

Pipe B can fill in 30 mins

Pipe B can do work in 1 minute =

Pipe C can empty the same in 40 mins

Pipe C can do work in 1 minute =

So, they can do work together in 1 minute =

=

They can fill part in minutes = 1

They can fill full tank in minutes =

=

Hence the time taken to fill the tank is minutes
5 Months agoHelpfull: Yes(0) No(0)

Pipe A can fill in 20 minutes and Pipe B in 30 mins and Pipe C can empty the same in 40 mins.If all of them work together, find the time taken to fill the tank

(a) 17 1/7 mins (b) 20 mins (c) 8 mins (d) none of these