A Train crosses A man standing on a platform which is 240 mtrs long in 13 secs & the platform itself in 25 secs. What was the speed of the train?

• Ans: 20 m/sec
  Let the length of train be x and speed of train be y m/sec
  speed= distance/time
  speed = x/13 ; speed = (x+240)/25
  x/13=(x+240)/25
  12x=3120 ;x=260 m
  speed = 260/13 =20 m/sec
• 14 years agoHelpfull: Yes(4) No(1)
• Ans: 72 km/hr or 20 m/sec
  Let the length of train be x
  speed of train = x/13 =(x+240)/25 >> 12x=3120 >> x=260
  speed of train=260/13 =20 m/sec >> 72 km/hr
• 14 years agoHelpfull: Yes(0) No(1)
• 20 m/s.....
  because first train crosses the man in 13 sec means the train covered the distance itself....but it takes 25 sec itself and flatform.... so it takes 12 sec to cross the 240 m......
• 14 years agoHelpfull: Yes(0) No(1)