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Numerical Ability
Algebra
Find out the greatest possible number for which 30% of that number is less than 100?
1) 331
2) 335
3) 325
4) 333
5) 328
Read Solution (Total 11)
-
- 30% of 331=99.3
30% of 335=100.5
30% of 325=97.5
30% of 333=99.9
30% of 328=98.4
so,the greatest possible number for which 30% of that number is less than 100 is 333 i.e 99.9
so, ans is 333.
- 13 years agoHelpfull: Yes(11) No(0)
- 333
30% of 333 is 99.9. - 13 years agoHelpfull: Yes(2) No(1)
- (30/100)*100=333.33
thus taking the whole no we get 333.
thus 30% of 333 is 99.9
so the ans is 333 - 13 years agoHelpfull: Yes(1) No(0)
- x*(30/100)=100
x=(10000/30)
x=333.3 - 9 years agoHelpfull: Yes(1) No(0)
- lets x be that no.
therefore 30x/1003xx - 13 years agoHelpfull: Yes(0) No(1)
- 30% of 333is 99.9,so this is the greatest possible value
- 13 years agoHelpfull: Yes(0) No(0)
- Let the number be x;
x*30% - 10 years agoHelpfull: Yes(0) No(1)
- Let x be the no
x*30/100 is 30% of x
so x*30/100 - 10 years agoHelpfull: Yes(0) No(0)
- ans:333
Let the number be x
give in question statement is that 30% of that number(i.e x) is less than 100
i.e 30/100 *x - 100
3x/10=100
3x=100*10
x=333.33 apprx 333 - 9 years agoHelpfull: Yes(0) No(0)
- 333*3/10 = 99.9 which is
- 7 years agoHelpfull: Yes(0) No(0)
- the solution is 333
- 5 years agoHelpfull: Yes(0) No(0)
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