There are a certain no of sweets in a box.They are divided in such a way that the person gets 1/4 of the whole get thrice of others.Find the no.of people amongest when the sweets were distributed.

• Qn is not clear.
  
  As per my u8nderstanding, If there are 12 swwets , one person will get 3 sweets and other 9 persons will have 1 each.
  
  So 12 sweets among divided 10 persons.
  
  Many solutions are possible according to this interpretation.
• 13 years agoHelpfull: Yes(8) No(2)
• Suppose their is x sweets.So First will get x/4.
  Remaining amount=x - x/4 = 3x/4.
  suppose single man will get y
  so 3y = x / 4
  y= x / 12.
  so 3x / 4 distribute in (3x/4) / (x/12).
  =9
  So total man = 9 + 1. =10.
• 13 years agoHelpfull: Yes(3) No(0)
• three possibility only
  if 1 person get 1/4 of whole then 9 person will get 1/12 of sweet so total 10 person
  if 2 person get 1/4 of whole then 6 person will get 1/12 of sweet so total 8 person
  if 3 person get 1/4 of whole then 3 person will get 1/12 of sweet so total 6 person will get sweet
  So question should be clear enough to find single answer
• 13 years agoHelpfull: Yes(2) No(1)
• give a person with 1/4 has three times as others so consider him as 3x sweets
  others contain x seats each
  now 3x=1/4 x=1/12
  now as we got prob then
  1/4+n(1/12)=1
  we get n=9
  and including d person containg 1/4 share we get 9+1 persons=10 persons
• 13 years agoHelpfull: Yes(2) No(0)