A man bought some oranges at the rate of 3 oranges for one rupee and equal number of oranges at the rate of 2 oranges for one rupee. What is his profit, if he sells 2 oranges for one rupee.

• profit =0.50paisa
  c.p=1rp(for 3 oranges) and 1.50ps(for 2 oranges at 1rp,1 orange at 0.50ps)=2.5rp
  s.p=3(total oranges=6,and two oranges cost=1rp)
  hence profit=c.p-s.p=3-2.5=0.5=5/100=20%
  
  
  
• 11 years agoHelpfull: Yes(2) No(0)
• Let us take LCM of quantities purchased and sold i.e. LCM of 3, 2 and 2 is 6.
  Now, cost price of 6 oranges @ 3 oranges for a rupee = 13 x 6 = Rs. 2
  And, cost price of 6 oranges @ 2 oranges for a rupee = 12 x 6 = Rs. 3
  Therefore, Cost price of 12 (i.e. 6 + 6) oranges = Rs. 2 + Rs. 3 = Rs. 5
  Selling price of 12 oranges = 12 x 12 = Rs. 6
  Profit = Rs. 6 - Rs. 5 = Re. 1 on Rs. 5
  Therefore, Profit percent = 15 = 20%
• 11 years agoHelpfull: Yes(1) No(0)
• profit is 20%
  
  c.p = 1( 3 for one rupee) + 1.5( same no of apples at 2 for one rupee)
  c.p= 2.5
  now s.p = 3
  s.p-c.p=3-2.5=0.5
• 11 years agoHelpfull: Yes(1) No(0)
• Equal no of oranges cought in the following cases:
  taking rupees in paisa,
  3 oranges = 100 paisa
  2 oranges = 100 paisa
  adding the above:-
  5 oranges = 200 paisa
  c.p of 1 orange = 40 paisa
  
  selling oranges:
  2 oranges = 100 paisa
  S.P of 1 orange = 50 paisa
  
  profit=(50-40)=10 paisa
  
  profit % =(10/40)*100= 25% Ans.
• 11 years agoHelpfull: Yes(0) No(0)