in how many 15 people seated around two tables with seating capacity of 7 and 8 people.
a. 15c7*15c8
b. 15c7*6!*!7
c 15c7*!7
d. 15c7*!6

• out of 15 people 7 people can be choosen in 15C7 ways for table1 and rest for table2.
  
  now in table1 7 people can sit (7-1)!ways or 6!ways ans 8 people can sit (8-1)!ways [rule for circular permutation]
  
  so 15c7*6!*7! will be the ans
• 10 years agoHelpfull: Yes(15) No(4)
• @shiva : then 15c8 * 6! * 7! could also be answer.
• 10 years agoHelpfull: Yes(4) No(2)
• Yes nCr=nCn-r both are same...........
• 10 years agoHelpfull: Yes(4) No(1)
• Ans is: 15c7*6!*7!
• 10 years agoHelpfull: Yes(1) No(0)
• other answers are also possible
  15c8*7!8!
• 10 years agoHelpfull: Yes(0) No(2)