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in how many 15 people seated around two tables with seating capacity of 7 and 8 people.
a. 15c7*15c8
b. 15c7*6!*!7
c 15c7*!7
d. 15c7*!6
Read Solution (Total 5)
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- out of 15 people 7 people can be choosen in 15C7 ways for table1 and rest for table2.
now in table1 7 people can sit (7-1)!ways or 6!ways ans 8 people can sit (8-1)!ways [rule for circular permutation]
so 15c7*6!*7! will be the ans - 11 years agoHelpfull: Yes(15) No(4)
- @shiva : then 15c8 * 6! * 7! could also be answer.
- 11 years agoHelpfull: Yes(4) No(2)
- Yes nCr=nCn-r both are same...........
- 11 years agoHelpfull: Yes(4) No(1)
- Ans is: 15c7*6!*7!
- 11 years agoHelpfull: Yes(1) No(0)
- other answers are also possible
15c8*7!8! - 11 years agoHelpfull: Yes(0) No(2)
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