A survey of movie goers from five cities A, B, C, D and E is summarized below. The first column gives the percentage of viewers in each city who watch less than one movie a week. The second column gives the total number of viewers who view one or more than movies per week.
option
City I II
A 60 2400
B 20 3000
C 85 2400
D 55 2700
E 75 8000

• arre where is the question..
• 11 years agoHelpfull: Yes(14) No(1)
• [1] How many viewers in the city C watch less than one movie a week?
  a. 2040
  b. 13600
  c. 16000
  d. 3600
  [2] Which city has the highest number of viewers who watch less than one movie a week?
  a. City E
  b. City D
  c. City B
  d. City C
  [3] A city with second lowest number of movie watchers is
  a. City E
  b. City D
  c. City B
  d. City C
  [4] The total number of all movie goers in the five cities who watch less than one movie per week is
  a. 50000
  b. 36000
  c. 18500
  d. 45250
• 11 years agoHelpfull: Yes(3) No(0)
• [1]13600
  [2]city c
  [3]city d
  [4]45250
• 11 years agoHelpfull: Yes(2) No(9)
• formulae( only applicable to dis problem, can be easily derived if you calculate it manually)
  1. to find no of viewers in a city 'who watch less than one movie per week' :
  = ((value of column 1)/(100-value of column 1))*(value of column 2)
  using it we'll get:
  no of viewers watching less than one movie a week for A,B,C,D & E are respectively 3600(=(60/40)*2400),750,13600,3300 and 2400
  and now we can answer the questions:
  1. (b).13600
  2. (a). city E
  3. (b). city D
  4. (d). sum= 45250
• 11 years agoHelpfull: Yes(2) No(0)